Java_Datatypes.java

/*Java has 8 primitive data types; char, boolean, byte, short, int, long, float, and double. For this exercise,
we'll work with the primitives used to hold integer values (byte, short, int, and long):

A byte is an 8-bit signed integer.
A short is a 16-bit signed integer.
An int is a 32-bit signed integer.
A long is a 64-bit signed integer.
Given an input integer, you must determine which primitive data types are capable of properly storing that input.

*/
import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class JavaDatatypes {

    static String whoCanFitTheNumber(String numString)
    {
        String answer = "";
        try{
            long num = Long.parseLong(numString);
            answer = numString + " can be fitted in:\n";
            if((num<=Byte.MAX_VALUE) && (num>=Byte.MIN_VALUE)){
                answer = answer.concat("* byte\n* short\n* int\n* long");
            }else if((num <= Short.MAX_VALUE) && (num >= Short.MIN_VALUE)){
                answer = answer.concat("* short\n* int\n* long");
            }else if((num <= Integer.MAX_VALUE) && (num >= Integer.MIN_VALUE)){
                    answer = answer.concat("* int\n* long");
            }else{
                    answer = answer.concat("* long");
            }
        }catch (NumberFormatException e){
            answer = numString+" can't be fitted anywhere.";
        }
        return answer;
    }
    public static void main(String[] args) {
        /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution.
        */
        Scanner scanner = new Scanner(System.in);
        int numTestCases = scanner.nextInt() ;
        scanner.nextLine();
        for(int i=0; i<numTestCases;i++){
            String numString = scanner.nextLine();
            System.out.println(whoCanFitTheNumber(numString));
        }
    }
}