into_to_python_notes

while loop

while(True):
    entry = input(Enter number or 'x' to quit: ")
    if entry == 'x':
        break
num = float(entry)

whenever you write a program, write it piece by and piece and test it

if you want to skip a line in output you would type and additional print() function before your print function so the presentation of output is presentable

if you wrap your or's with parenthesis then indentation shouldnt matter

"""
Write a while loop to count the number of consonants in the string
 "Computer". (hint: check while not vowel)
"""

# =============================================================================
# word = "Computer"
# count = 0
# total = 0 #how many consonants
# 
# while count < len(word):
#     if (word[count] != 'a' or 
#         word[count] != 'e' or
#         word[count] != 'i' or
#         word[count] != 'o' or
#         word[count] != 'u'):
#         total = total + 1
#     count = count + 1
# 
# print()
# print(f"{total}")
# =============================================================================
        
word = "Computer"
count = 0
total = 0 #how many consonants

while count < len(word):
    if word[count] not in ['a', 'e', 'i', 'o', 'u']:
        total = total + 1
    count = count + 1

print()
print(f"{total}")        


#we want to print three rows of % with 6 columns, the problem right now is that when j reaches 6 it meets the condition
i = 1

while i <= 3:
    print("%", end='')
    i = i + 1
    while j <= 6: