diff --git a/AP1403 - RegEx/src/main/java/Exercises.java b/AP1403 - RegEx/src/main/java/Exercises.java
index 8ca6090..9ec7bbb 100644
--- a/AP1403 - RegEx/src/main/java/Exercises.java	
+++ b/AP1403 - RegEx/src/main/java/Exercises.java	
@@ -1,3 +1,6 @@
+import java.time.LocalDate;
+import java.time.format.DateTimeFormatter;
+import java.time.format.DateTimeParseException;
 import java.util.ArrayList;
 import java.util.List;
 import java.util.regex.Matcher;
@@ -8,8 +11,12 @@ public class Exercises {
     /*
         complete the method below, so it will validate an email address
      */
-    public boolean validateEmail(String email) {
-        String regex = ""; // todo
+
+    public static boolean validateEmail(String email) {
+
+        String regex = ""; 
+        regex = "^[a-zA-Z0-9._%+-]+@[a-zA-Z0-9.-]+\\\\.[a-zA-Z]{2,}$"; // (regex).الگو  برای اعتبار سنجی یک ادرس ایمیل که بر گرفته از چت جی بی تی است 
+
         Pattern pattern = Pattern.compile(regex);
         Matcher matcher = pattern.matcher(email);
 
@@ -21,11 +28,36 @@ public boolean validateEmail(String email) {
         note that it should be in british or american format
         if there's no match for a date, return null
      */
-    public String findDate(String string) {
-        // todo
+    public static String findDate(String string) {
+
+        String americanDateFormat = "\\d{2}/\\d{2}/\\d{4}";
+        String britishDateFormat = "\\d{2}/\\d{2}/\\d{4}";   // regex برای تشخیص تاریخ به فرمت آمریکایی و بریتانیایی باالگوی
+
+        String combinedRegex = "(" + americanDateFormat + ")|(" + britishDateFormat + ")";
+        Pattern pattern = Pattern.compile(combinedRegex);
+        Matcher matcher = pattern.matcher(string);
+
+        if (matcher.find()) {
+            String dateString = matcher.group();
+
+            try {
+                 LocalDate date = LocalDate.parse(dateString, DateTimeFormatter.ofPattern("MM/dd/yyyy"));
+                 return date.format(DateTimeFormatter.ISO_DATE);
+                 } 
+                 catch (DateTimeParseException e) {
+                    try {
+                        LocalDate date = LocalDate.parse(dateString, DateTimeFormatter.ofPattern("dd/MM/yyyy"));
+                        return date.format(DateTimeFormatter.ISO_DATE);
+                    }
+                     catch (DateTimeParseException ex) {
         return null;
+          }
+     } 
+}
+         else{
+                 return null;
+            }
     }
-
     /*
         given a string, implement the method to detect all valid passwords
         then, it should return the count of them
@@ -36,9 +68,19 @@ public String findDate(String string) {
         - at least one number and at least a special char "!@#$%^&*"
         - has no white-space in it
      */
-    public int findValidPasswords(String string) {
-        // todo
-        return -1;
+    public static int findValidPasswords(String string) {
+
+        String passwordRegex = "(?=.*[a-z])(?=.*[A-Z])(?=.*\\\\d)(?=.*[!@#$%^&*])(?=\\\\S+$).{8,}"; // الگو یافت شده از سرچ کردن 
+
+        Pattern pattern = Pattern.compile(passwordRegex);
+        Matcher matcher = pattern.matcher(string);
+
+        int count = 0;
+
+        while (matcher.find()) {
+            count++;
+        }
+        return count;
     }
 
     /*
@@ -47,13 +89,75 @@ public int findValidPasswords(String string) {
 
         note: your implementation should be case-insensitive, e.g. Aba -> is palindrome
      */
-    public List<String> findPalindromes(String string) {
+    public static List<String> findPalindromes(String string) {
         List<String> list = new ArrayList<>();
-        // todo
+
+        String[] words = string.toLowerCase().split("\\s+"); 
+
+        for (String word : words) {
+                       if (word.length() >= 3 && isPalindrome(word)) {
+                list.add(word);
+            }
+        }
+
         return list;
     }
 
+    //زدن یک متد اضافی برای چک کردن پالیندروم بودن یا نبودن یک حرف 
+
+    private static boolean isPalindrome(String word) {
+        int left = 0;
+        int right = word.length() - 1;
+
+        while (left < right) {
+            if (word.charAt(left) != word.charAt(right)) {
+                return false;
+            }
+            left++;
+            right--;
+        }
+
+        return true;
+        }
+
+
+
     public static void main(String[] args) {
-        // you can test your code here
+
+        Exercises validator = new Exercises();
+
+        String email1 = "test@example.com";
+        String email2 = "invalid-email";
+        String email3 = "another.test@sub.example.co.uk";
+
+        System.out.println(email1 + " is valid: " + validator.validateEmail(email1)); 
+        System.out.println(email2 + " is valid: " + validator.validateEmail(email2)); 
+        System.out.println(email3 + " is valid: " + validator.validateEmail(email3));
+
+        //چک کردن کد دوم 
+
+        String text1 = "امروز تاریخ 10/25/2024 است.";
+        String text2 = "تاریخ جلسه 25/10/2024 است.";
+        String text3 = "هیچ تاریخی در این متن وجود ندارد.";
+
+        System.out.println("تاریخ در متن 1: " + findDate(text1)); 
+        System.out.println("تاریخ در متن 2: " + findDate(text2));
+        System.out.println("تاریخ در متن 3: " + findDate(text3)); 
+
+        //چک کردن کد سوم 
+
+        String input = "ValidPassword123! and another Valid@1234 and one more validPass#2023 and InvalidPassword but validPass@1!";
+        int validPasswordCount = findValidPasswords(input);
+        System.out.println("Number of valid passwords: " + validPasswordCount); 
+
+        // چک کردن اخرین کد 
+
+        String Input = "Aba racecar level kayak notapalindrome";
+        List<String> palindromicWords = findPalindromes(Input);
+        System.out.println("Palindromic words: " + palindromicWords);
+
+
+
     }
+
 }