diff --git a/02_activities/assignments/Cohort_8/assignment1.sql b/02_activities/assignments/Cohort_8/assignment1.sql
index c992e3205..0ede5506e 100644
--- a/02_activities/assignments/Cohort_8/assignment1.sql
+++ b/02_activities/assignments/Cohort_8/assignment1.sql
@@ -4,17 +4,27 @@
 
 --SELECT
 /* 1. Write a query that returns everything in the customer table. */
-
+SELECT * FROM customer
 
 
 /* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, 
 sorted by customer_last_name, then customer_first_ name. */
-
+SELECT *
+FROM customer
+GROUP by customer_last_name, customer_first_name
+LIMIT 10
 
 
 --WHERE
 /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
-
+SELECT 
+cp.product_id,
+vendor_id,
+product_name
+FROM customer_purchases as cp
+INNER JOIN product as p
+ON cp.product_id = p.product_id
+WHERE cp.product_id IN (4, 9)
 
 
 /*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), 
@@ -23,10 +33,15 @@ filtered by customer IDs between 8 and 10 (inclusive) using either:
 	2.  one condition using BETWEEN
 */
 -- option 1
-
+# logic of price is added line 41
+SELECT *, ROUND((quantity * cost_to_customer_per_qty), 2) AS price 
+FROM customer_purchases 
+WHERE customer_id >= 8 AND customer_id <= 10;
 
 -- option 2
-
+SELECT *, ROUND((quantity * cost_to_customer_per_qty), 2) AS price 
+FROM customer_purchases 
+WHERE customer_id BETWEEN 8 AND 10;
 
 
 --CASE
@@ -34,19 +49,40 @@ filtered by customer IDs between 8 and 10 (inclusive) using either:
 Using the product table, write a query that outputs the product_id and product_name
 columns and add a column called prod_qty_type_condensed that displays the word “unit” 
 if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
-
+SELECT
+product_id,
+product_name,
+CASE 
+	WHEN product_qty_type = 'unit' then 'unit'
+	ELSE 'bulk'
+END AS prod_qty_type_condensed
+FROM product
+GROUP BY product_id
 
 
 /* 2. We want to flag all of the different types of pepper products that are sold at the market. 
 add a column to the previous query called pepper_flag that outputs a 1 if the product_name 
 contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
-
+SELECT
+product_name,
+CASE
+	WHEN LOWER (product_name) LIKE '%pepper%' then '1'
+	ELSE '0'
+END AS pepper_flag
+FROM product
 
 
 --JOIN
 /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the 
 vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
-
+SELECT
+v.vendor_name,
+vb.market_date,
+v.vendor_id
+FROM vendor as v
+INNER JOIN vendor_booth_assignments as vb
+ON v.vendor_id = vb.vendor_id
+GROUP BY v.vendor_name, vb.market_date
 
 
 
@@ -55,7 +91,15 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t
 -- AGGREGATE
 /* 1. Write a query that determines how many times each vendor has rented a booth 
 at the farmer’s market by counting the vendor booth assignments per vendor_id. */
-
+SELECT
+v.vendor_id,
+v.vendor_name,
+booth_number,
+COUNT (booth_number) as booth_count
+FROM vendor AS v
+INNER JOIN  vendor_booth_assignments as vb
+ON v.vendor_id = vb.vendor_id
+GROUP BY v.vendor_name, booth_number
 
 
 /* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper 
@@ -63,7 +107,16 @@ sticker to everyone who has ever spent more than $2000 at the market. Write a qu
 of customers for them to give stickers to, sorted by last name, then first name. 
 
 HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
-
+SELECT
+c.customer_last_name,
+c.customer_first_name,
+SUM (cp.quantity*cp.cost_to_customer_per_qty) as total_spent
+FROM customer as c
+INNER JOIN customer_purchases as cp
+ON c.customer_id = cp.customer_id
+GROUP BY c.customer_last_name, c.customer_first_name
+HAVING SUM( cp.quantity*cp.cost_to_customer_per_qty) >2000
+ORDER BY c.customer_last_name, c.customer_first_name
 
 
 --Temp Table
@@ -77,7 +130,11 @@ When inserting the new vendor, you need to appropriately align the columns to be
 -> To insert the new row use VALUES, specifying the value you want for each column:
 VALUES(col1,col2,col3,col4,col5) 
 */
-
+CREATE TABLE temp.new_vendor AS
+SELECT *
+FROM vendor;
+INSERT INTO temp.new_vendor (vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name)
+VALUES (10,  "Thomas Superfood Store", 'Fresh Focused', 'Rosenthal', 'Thomas');
 
 
 -- Date
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