From 275e0152da700c5f01cab737b1443be014bfd76d Mon Sep 17 00:00:00 2001
From: Rahul Ankam <rahulankam1234@gmail.com>
Date: Mon, 3 Mar 2025 12:26:24 +0530
Subject: [PATCH] Completed JS Basic Algorithms Lab

---
 js/index.js | 49 +++++++++++++++++++++++++++++++++++++++++++++++--
 1 file changed, 47 insertions(+), 2 deletions(-)

diff --git a/js/index.js b/js/index.js
index 59e4af7..68e2b97 100644
--- a/js/index.js
+++ b/js/index.js
@@ -1,6 +1,51 @@
+console.log("I'm ready!");
+
+
 // Iteration 1: Names and Input
-//
-// Iteration 2: Conditionals
+let hacker1 = "John";
+console.log(`The driver's name is ${hacker1}`);
+
+let hacker2 = "Alice";
+console.log(`The navigator's name is ${hacker2}`);
 
 
+// Iteration 2: Conditionals
+if (hacker1.length > hacker2.length) {
+    console.log(`The driver has the longest name, it has ${hacker1.length} characters.`);
+  } else if (hacker1.length < hacker2.length) {
+    console.log(`It seems that the navigator has the longest name, it has ${hacker2.length} characters.`);
+  } else {
+    console.log(`Wow, you both have equally long names, ${hacker1.length} characters!`);
+  }
+  
+
 // Iteration 3: Loops
+// Print driver's name in uppercase with spaces
+console.log(hacker1.toUpperCase().split("").join(" "));
+
+// Print navigator's name in reverse
+console.log(hacker2.split("").reverse().join(""));
+
+// Lexicographic order
+if (hacker1 < hacker2) {
+  console.log("The driver's name goes first.");
+} else if (hacker1 > hacker2) {
+  console.log("Yo, the navigator goes first definitely.");
+} else {
+  console.log("What?! You both have the same name?");
+}
+
+//Bonus 1: Word Count & "et" Count
+
+let lorem = "Lorem ipsum et dolor et sit amet...";
+let wordCount = lorem.split(/\s+/).length;
+let etCount = (lorem.match(/\bet\b/g) || []).length;
+console.log(`Word count: ${wordCount}, "et" count: ${etCount}`);
+
+//Bonus 2: Palindrome Check
+
+let phraseToCheck = "A man, a plan, a canal, Panama!";
+let cleanedPhrase = phraseToCheck.toLowerCase().replace(/[^a-z0-9]/g, "");
+let reversedPhrase = cleanedPhrase.split("").reverse().join("");
+
+console.log(cleanedPhrase === reversedPhrase ? "It's a palindrome!" : "Not a palindrome.");