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0221.cpp
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137 lines (125 loc) · 3.34 KB
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class Solution {
public:
int maximalSquare(vector<vector<char>> &matrix) {
// return func1(matrix);
// return func2(matrix);
// return func3(matrix);
return func4(matrix);
}
//** 1. recursive
int func1(vector<vector<char>> &matrix) {
if (matrix.empty()) {
return 0;
}
int ret = 0;
for (int i = 0; i < matrix.size(); i++) {
for (int j = 0; j < matrix[i].size(); j++) {
ret = max(ret, helper1(matrix, i, j));
}
}
return ret * ret;
}
int helper1(vector<vector<char>> &matrix, int i, int j) {
if (i >= matrix.size() || j >= matrix[i].size()) {
return 0;
}
if (matrix[i][j] == '0') {
return 0;
}
int a = helper1(matrix, i, j + 1);
int b = helper1(matrix, i + 1, j);
int c = helper1(matrix, i + 1, j + 1);
return min(a, min(b, c)) + 1;
}
//** 2. recursize + memo
int func2(vector<vector<char>> &matrix) {
if (matrix.empty()) {
return 0;
}
int ret = 0;
vector<vector<int>> memo(matrix.size(), vector<int>(matrix[0].size(), -1));
for (int i = 0; i < matrix.size(); i++) {
for (int j = 0; j < matrix[i].size(); j++) {
ret = max(ret, helper2(matrix, i, j, memo));
}
}
return ret * ret;
}
int helper2(vector<vector<char>> &matrix, int i, int j,
vector<vector<int>> &memo) {
if (i >= matrix.size() || j >= matrix[i].size()) {
return 0;
}
if (matrix[i][j] == '0') {
return 0;
}
if (memo[i][j] != -1) {
return memo[i][j];
}
int a = helper1(matrix, i, j + 1);
int b = helper1(matrix, i + 1, j);
int c = helper1(matrix, i + 1, j + 1);
memo[i][j] = min(a, min(b, c)) + 1;
return memo[i][j];
}
//** 3. iterative + memo
int func3(vector<vector<char>> &matrix) {
if (matrix.empty()) {
return 0;
}
int M = matrix.size();
int N = matrix[0].size();
int ret = 0;
vector<vector<int>> memo(M, vector<int>(N, 0));
for (int i = M - 1; i >= 0; i--) {
for (int j = N - 1; j >= 0; j--) {
if (matrix[i][j] == '0') {
memo[i][j] = 0;
ret = max(ret, memo[i][j]);
continue;
}
if (i + 1 >= M || j + 1 >= N) {
memo[i][j] = 1;
ret = max(ret, memo[i][j]);
continue;
}
int a = memo[i][j + 1];
int b = memo[i + 1][j];
int c = memo[i + 1][j + 1];
memo[i][j] = min(a, min(b, c)) + 1;
ret = max(ret, memo[i][j]);
}
}
return ret * ret;
}
//** 3. iterative + 2N variables
int func4(vector<vector<char>> &matrix) {
if (matrix.empty()) {
return 0;
}
int M = matrix.size();
int N = matrix[0].size();
int ret = 0;
vector<vector<int>> memo(2, vector<int>(N, 0));
for (int i = M - 1; i >= 0; i--) {
for (int j = N - 1; j >= 0; j--) {
if (matrix[i][j] == '0') {
memo[i % 2][j] = 0;
ret = max(ret, memo[i % 2][j]);
continue;
}
if (i + 1 >= M || j + 1 >= N) {
memo[i % 2][j] = 1;
ret = max(ret, memo[i % 2][j]);
continue;
}
int a = memo[i % 2][j + 1];
int b = memo[(i + 1) % 2][j];
int c = memo[(i + 1) % 2][j + 1];
memo[i % 2][j] = min(a, min(b, c)) + 1;
ret = max(ret, memo[i % 2][j]);
}
}
return ret * ret;
}
};