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[3차] 방금그곡 #29
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[3차] 방금그곡 #29
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Summary of ChangesHello @dongglehada, I'm Gemini Code Assist1! I'm currently reviewing this pull request and will post my feedback shortly. In the meantime, here's a summary to help you and other reviewers quickly get up to speed! 이 PR은 주어진 멜로디 조각과 여러 음악 정보 목록을 비교하여, 해당 멜로디가 재생된 음악의 제목을 찾아 반환하는 Swift 솔루션을 도입합니다. 이 변경사항은 음표 표현의 복잡성을 처리하고, 음악 재생 시간을 정확하게 계산하며, 문제의 요구사항에 따라 최적의 일치 항목을 선택하는 견고한 방법을 제공합니다. Highlights
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Code Review
The pull request provides a solution for the 'Just That Song' problem. However, the code is vulnerable to Denial of Service (DoS) attacks due to runtime crashes (from force unwrapping and negative indices) and potential infinite loops when processing malformed input. Additionally, there are logic issues when handling multiple matching songs and inefficiencies from duplicate calculations within loops. It is recommended to use safe unwrapping, validate input ranges and formats, and optimize loop performance to ensure application stability and security.
| if playTime > resultPlayTime { | ||
| result = musicTitle | ||
| resultPlayTime = playTime | ||
| resultStartTime = startTime | ||
| } else if playTime == resultPlayTime { | ||
| if startTime < resultStartTime { | ||
| result = musicTitle | ||
| resultPlayTime = playTime | ||
| resultStartTime = startTime | ||
| } | ||
| } |
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문제의 조건에 따르면 재생 시간이 같을 경우, 먼저 입력된 음악 제목을 반환해야 합니다. 현재 코드는 startTime을 비교하여 더 일찍 시작한 음악을 선택하고 있는데, 이는 요구사항과 다릅니다. for 루프는 입력된 순서대로 순회하므로, 재생 시간이 더 긴 경우에만 결과를 갱신하면 '먼저 입력된' 조건이 자연스럽게 만족됩니다. 현재의 else if 블록은 잘못된 결과를 낼 수 있습니다. 아래와 같이 수정하여 재생 시간이 더 긴 경우에만 결과를 갱신하도록 하는 것이 올바릅니다. 이 수정과 함께 더 이상 필요 없는 resultStartTime 변수도 제거하는 것이 좋습니다.
if playTime > resultPlayTime {
result = musicTitle
resultPlayTime = playTime
}| while music.count < playTime { | ||
| music += toShortString(melody) | ||
| } |
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This while loop has a potential infinite loop vulnerability if toShortString(melody) returns an empty string and playTime is greater than 0, which can lead to CPU exhaustion and a Denial of Service (DoS). Additionally, toShortString(melody) is called in every iteration, which is an unnecessary repeated calculation as melody does not change within the loop. Consider pre-calculating shortMelody and adding a check for an empty string to prevent the infinite loop.
let shortMelody = toShortString(melody)
if !shortMelody.isEmpty {
while music.count < playTime {
music += shortMelody
}
}| music += toShortString(melody) | ||
| } | ||
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| if music.prefix(playTime).contains(toShortString(m)) { |
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There's a potential crash vulnerability here: if endTime is less than startTime, playTime will be negative, causing a runtime crash when passed to prefix(_:). Ensure playTime is non-negative before calling prefix. Additionally, toShortString(m) is called repeatedly inside the for loop, which is inefficient as m does not change. Pre-calculating shortM outside the loop would improve performance.
if playTime > 0, music.prefix(playTime).contains(toShortString(m)) {|
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| func toInt(_ timeString: String) -> Int { | ||
| let components = timeString.components(separatedBy: ":") | ||
| return (Int(components[0])! * 60) + Int(components[1])! |
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This code exhibits insecure data handling. Force unwrapping (!) during Int conversion and direct array index access without bounds checking can lead to a runtime crash if timeString is not in the expected 'HH:MM' format. This vulnerability can be exploited to trigger a Denial of Service (DoS) attack. It's crucial to avoid force unwrapping for safer code and robust input validation.
guard components.count >= 2, let hours = Int(components[0]), let minutes = Int(components[1]) else { return 0 }
return (hours * 60) + minutes| var resultStartTime = 0 | ||
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| for info in musicinfos { | ||
| let info = info.components(separatedBy: ",") |
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🔗 문제 링크
✔️ 소요된 시간
60분
📚 새롭게 알게된 내용
테스트 케이스 34번.. B#, E# 예외처리 해줘야하는거 질문하기 보고 알았음..