is doin

[bit-sercererx]

No description provided.

[AlhassanAli01]

This should be 17 % 3 because we're asking for the remainder.

[AlhassanAli01]

Declare a variable price and assign it the value 9.99.
This should be something like:
let price = 9.99;

[AlhassanAli01]

Declare another variable discount and assign it the value 0.20 and calculate the discounted price and log the result to the console.

[AlhassanAli01]

This is not what was required, please declare two variables like I mentioned in the comments above.
Then create a new variable called result which would divide the two numbers and round the result to the nearest integer using Math.round()

[AlhassanAli01]

This should return true, because both of these values are falsey values by default, meaning that false == false.

This would return false only when using the strict equals operator === which would also check for the types resulting in them being false.

[AlhassanAli01]

"true" is a string value and true is a boolean value, they do not equal the same thing, therefore this should evaluate to false

[AlhassanAli01]

Same goes here, this should be false because they're two different types of values.

[AlhassanAli01]

This should evaluate to false.
The reason NaN === NaN evaluates to false is because according to the IEEE 754 standard (which JavaScript follows for floating-point arithmetic), NaN values are considered unordered. This means that they are not equal to any other value, including other NaN values.

[AlhassanAli01]

This should be false.
In the expression "apple" > "pineapple", JavaScript compares the strings character by character from left to right. Since "a" comes before "p" in the alphabet, "apple" is considered "less than" "pineapple".

[AlhassanAli01]

This should evaluate to true.
Even though numerically 2 is less than 12, since we're comparing strings, the comparison is based on their lexicographical order. In this case, the string "2" is considered greater than the string "12" because "2" comes after "1".

[AlhassanAli01]

Checking the str to see if it's "apple" or "orange" should be written as the following:

console.log( str === "apple" || str === "orange")

[AlhassanAli01]

You forgot to check if the number is even, you can do so by writing the following:

console.log( num % 2 === 0 && num > 10 )

[AlhassanAli01]

To check if a number is divisible by another number, you should use the mod operator % and check if the value is equal to 0.

console.log( num % 3 === 0 && num % 5 === 0 )

[AlhassanAli01]

Using the search method with strings is a good approach, the return value of the search method is the index of the letter inside the string.
And since there's no "e" in our str variable, it will return -1.
We can use that with a comparison operator to print out true or false in the console:

console.log( str.search("e") !== -1 )

This will return true if it exists, and false if it doesn't.

[AlhassanAli01]

To check if the number is odd correctly you can do the following:

console.log( num % 2 === 1 )

Or

console.log( num % 2 !== 0 )

either way these expression will return true or false