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Homework-HangPerson #24

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58 changes: 56 additions & 2 deletions HangPerson/HangPerson/main.m
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Original file line number Diff line number Diff line change
Expand Up @@ -12,7 +12,61 @@ int main(int argc, const char * argv[]) {
@autoreleasepool {

// code goes here...

char word[5] = "pasta";
char dashes[5] = "_____";
char input;
char temp;
int guesses = 7; //Maximum tries.
int i;
int j;
int swaps = 5;


printf("Lets play a Hangman.\n");
printf("I'm thinking of a word. Can you guess it?\n");

for(i = 0; i < guesses; i++ ) {
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@mikekavouras mikekavouras Jun 22, 2015

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The condition here shouldn't be based on the number of guess because you could guess the word in 4 guesses. A while loop would be better in this situation. Something along the lines of:

int won = 0;
int lost = 0;
while (won == 0 && lost == 0) { 
  // play game
}


printf("select a letter: \n");

printf("%c %c %c %c %c", dashes[0], dashes[1], dashes[2], dashes[3], dashes[4]);
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@mikekavouras mikekavouras Jun 22, 2015

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This is very specific to a 5 character word. It would be better to loop from 0 to sizeof(dashes) and print out each letter individually.


scanf("%c", &input);



char vanish;
scanf("%c", &vanish);

for(j = 0; j < 5; j++) {
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@mikekavouras mikekavouras Jun 22, 2015

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Similar thing here. Instead of 5 you should use sizeof(word)


// positive match
if (input == word[j]) {

swaps--;

temp = word[j];
word[j] = dashes[j];
dashes[j] = temp;


printf("\n%c", dashes[j]);

}
if (swaps == 0) {
break;
}
}

}


if (guesses == 7) {
printf("You lost.");
} else {
printf("You win");
}

}
return 0;
}
}