Completed Assignment sql_join-and-group

part1.sql

@@ -0,0 +1,12 @@
+--* Write a query to display each customer’s name (as`Customer Name`) 
+--alongside the name of the employee who is responsible for that 
+--customer’s orders.The employee name should be in a single `Sales Rep`
+--column formatted as `lastName, firstName`. The output should be sorted alphabetically by customer name.
+
+USE mysqlsampledatabase;
+
+-- For space between the contact Last Name and contact First Name use ' '
+SELECT customerName AS 'Customer Name',
+CONCAT(contactLastName,' ',contactFirstName) AS 'Sales Rep'
+FROM customers
+ORDER BY customerName;

part2.sql

@@ -0,0 +1,48 @@
+--* Determine which products are most popular with our customers.
+--// Assuming that the most popular product is the most ordered
+USE mysqlsampledatabase;
+
+SELECT productCode, SUM(quantityOrdered) AS 'Popular Product' from orderdetails
+GROUP BY productCode
+ORDER BY SUM(quantityOrdered) DESC;
+
+-- Bringing in the customer angle from the customerNumber in Orders table
+--Getting customerNumber instead of Customer Name and productCode intsead
+--of Product Name using this query.
+SELECT O.customernumber, OD.productCode, SUM(OD.quantityOrdered) Popular 
+FROM orderdetails OD INNER JOIN orders O
+ON O.ordernumber = OD.ordernumber
+GROUP BY O.customernumber, OD.productCode
+ORDER BY Popular Desc;
+
+--Finally using a subquery, I could get the desired popular product
+-- Names along with the Customer Names.
+
+Select C.customerName 'Customer Names', P.productName 'Product Names', Popularproduct.Popular
+from customers C, products P,
+( SELECT O.customernumber , OD.productCode, SUM(OD.quantityOrdered) Popular 
+FROM orderdetails OD INNER JOIN orders O
+ON O.ordernumber = OD.ordernumber
+GROUP BY O.customernumber, OD.productCode
+ORDER BY Popular Desc ) Popularproduct
+where C.customerNumber = Popularproduct.customernumber
+AND P.productCode = Popularproduct.productCode
+GROUP BY customerName; --Gives the most popular product for each customer
+
+--* For each product, list the total quantity ordered along with the total
+--sale generated (total quantity ordered * priceEach) for that product.
+
+SELECT p.productName 'Product Name', sum(od.quantityOrdered) 'Total # Ordered',
+ sum(quantityOrdered*priceEach)'Total Sale' 
+ FROM products p JOIN orderdetails od
+ ON p.productCode=od.productCode
+ GROUP BY productName; 
+
+--* The column headers should be `Product Name`, `Total # Ordered` and
+--`Total Sale`. List the products by `Total Sale` descending.
+SELECT p.productName 'Product Name', sum(od.quantityOrdered) 'Total # Ordered',
+ sum(quantityOrdered*priceEach)'Total Sale' 
+ FROM products p JOIN orderdetails od
+ ON p.productCode=od.productCode
+ GROUP BY productName
+ ORDER BY 'Total Sale' DESC;

part3.sql

@@ -0,0 +1,7 @@
+--A query which lists order status and the # of orders with that status.
+--* Column headers should be `Order Status` and `# Orders`.
+--* Sort alphabetically by `status`.
+SELECT o.status 'Order Status', COUNT(orderNumber) '# Orders'
+FROM orders o
+GROUP BY status;
+ORDER BY status;  --sorting alphabetically

part4.sql

@@ -0,0 +1,11 @@
+--Write a query to list, for each product line, the total # of products 
+--sold from that product line.
+--* The first column should be `Product Line` and the second should be 
+--`# Sold`.* Order by the second column descending.
+
+SELECT p.productline 'Product Line', COUNT(od.quantityOrdered) '# Sold'
+FROM products p INNER JOIN orderdetails od
+ON p.productCode=od.productCode
+GROUP BY productLine
+ORDER BY COUNT(od.quantityOrdered) DESC;
+

part5.sql

@@ -0,0 +1,17 @@
+--For each employee who represents customers, output the total # of orders
+--that employee’s customers have placed alongside the total sale amount of those orders.
+--* The employee name should be output as a single column named `Sales Rep` formatted
+ --as `lastName, firstName`.
+--* The second column should be titled `# Orders` and the third should be `Total Sales`.
+--* Sort the output by `Total Sales` descending.
+--* Only (and all) employees with the job title `Sales Rep` should be included in the output, 
+--and if the employee made no sales the `Total Sales` should display as `0.00`.
+
+SELECT concat(lastName,' ',firstName) AS 'Sales Rep', COUNT(quantityOrdered) 
+AS 'Total # Ordered', COUNT(quantityOrdered)*SUM(priceEach) AS 'Total Sales'
+FROM employees e,customers c,orderdetails od, orders o
+WHERE c.salesRepEmployeeNumber = e.employeeNumber 
+AND o.orderNumber = od.orderNumber 
+AND e.jobTitle = 'Sales Rep'
+GROUP BY employeeNumber
+ORDER BY  COUNT(quantityOrdered)*SUM(priceEach) DESC;

part6.sql

@@ -0,0 +1,12 @@
+--Write a query to output the month (January, February, etc.), 4-digit year, and total
+ --sales for that month.
+--* The first column should be labeled `Month`, the second `Year`, and the third
+-- should be `Payments Received`.
+--* Values in the third column should be formatted as numbers with two decimals – 
+--for example: `694,292.68`.
+
+SELECT MONTH(paymentDate) AS Month, YEAR(paymentDate) AS Year, SUM(amount) AS 
+'Payments Received'
+FROM payments
+GROUP by Month
+ORDER BY Year, Month;