BenchmarkHash function, the parameter h is changed from maphash to *maphash.Hash#8
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Montana wants to merge 1 commit intoredpanda-data:releasefrom
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BenchmarkHash function, the parameter h is changed from maphash to *maphash.Hash#8Montana wants to merge 1 commit intoredpanda-data:releasefrom
BenchmarkHash function, the parameter h is changed from maphash to *maphash.Hash#8Montana wants to merge 1 commit intoredpanda-data:releasefrom
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…Hash` to `*maphash.Hash` In the `benchmarkHash` function, the parameter `h` is changed from `maphash.Hash` to `*maphash.Hash`. This is because `maphash.Hash` is a struct, not an interface, and should be passed as a pointer. In the `BenchmarkMaphash` function, when calling `benchmarkHash`, the `&` operator is added before `h` to pass the address of `h` instead of the value.
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BenchmarkHash function, the parameter h is changed from maphashHash to *maphash.HashBenchmarkHash function, the parameter h is changed from maphash to *maphash.Hash
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Hi @Montana - you probably want to file this upstream at tinygo-org/tinygo 😄 |
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In the
benchmarkHashfunction, the parameterhis changed frommaphash.Hashto*maphash.Hash. This is becausemaphash.Hashis a struct, not an interface, and should be passed as a pointer.It should also be noted in the
benchmarkHashnfunction, the size of the sum slice was set to4, which may not be sufficient for all hash implementations. Instead, it should useh.Size()to determine the appropriate size based on the hash implementation.The blame is below:
https://github.com/redpanda-data/tinygo/blame/b8498403dd57cdf373280f663d67ffb5bb7eae44/tests/runtime/memhash_test.go#L11
In the
BenchmarkMaphashfunction, when callingbenchmarkHash, the&operator is added beforehto pass the address ofhinstead of the value.The blame is below:
https://github.com/redpanda-data/tinygo/blame/b8498403dd57cdf373280f663d67ffb5bb7eae44/tests/runtime/memhash_test.go#L15
Cheers,
Michael Mendy