Added Hamming.c

Hamming.c

@@ -0,0 +1,42 @@
+#include<stdio.h>
+#include<string.h>
+void main()
+{
+    int d,c,i, length, count = 0,n;
+    int  s1[100], s2[100];
+    printf("length of s1 and s2 \n");
+    scanf("%d",&n);
+    printf("Enter s1 : ");
+    for(i=0;i<n;i++)
+    {
+    scanf("%d", &s1[i]);
+    }
+    printf("Enter s2 : ");
+    for(i=0;i<n;i++)
+    {
+        scanf("%d", &s2[i]);
+    }
+    for(i=0;i<n;i++)
+    {
+     if(s1[i]!=s2[i])
+     {
+         count=count+1;
+     }
+    }
+
+    printf("\nHamming Distance : %d\n", count);
+    if(count==0)
+    {
+     printf("no error ");
+    }
+    else
+    {
+
+    d=count-1;
+	c=(count-1)/2;
+     printf("error bits that can be detected = %d\n",d);
+     printf("error bits that can be corrected= %d",c);
+    }
+
+    getch();
+}

anagram.cpp

@@ -0,0 +1,49 @@
+// C++ program to check if two strings
+// are anagrams of each other
+#include <bits/stdc++.h>
+using namespace std;
+#define NO_OF_CHARS 256
+
+bool areAnagram(char* str1, char* str2)
+{
+	// Create a count array and initialize all values as 0
+	int count[NO_OF_CHARS] = { 0 };
+	int i;
+
+	// For each character in input strings, increment count
+	// in the corresponding count array
+	for (i = 0; str1[i] && str2[i]; i++) {
+		count[str1[i]]++;
+
+		count[str2[i]]--;
+
+	}
+
+	// If both strings are of different length. Removing
+	// this condition will make the program fail for strings
+	// like "aaca" and "aca"
+	if (str1[i] || str2[i])
+		return false;
+
+	// See if there is any non-zero value in count array
+	for (i = 0; i < NO_OF_CHARS; i++)
+		if (count[i])
+			return false;
+	return true;
+}
+
+// Driver code
+int main()
+{
+	char str1[] = "geeks@forgeeks";
+	char str2[] = "for@geeksgeeks";
+
+	// Function call
+	if (areAnagram(str1, str2))
+		cout << "The two strings are anagram of each other";
+	else
+		cout << "The two strings are not anagram of each "
+				"other";
+
+	return 0;
+}