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Needed to divide a timespec by an integer number
added timespec_div description
fixed some errors in TEST_DIV_FUNC
Fixes for 32 bits systems
Fixes for 32 bits
Fixes
Rewrite the function to make it work for 32 bits
Author
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Sorry for the mess, i have some issues making it work for i386, do you have any suggestion to make it work without losing precision? |
Owner
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Hi G.Pasotti, Thanks for this, mostly looks good to me although I'd rename it to something like I haven't tested it, I think something like this might handle the rounding correctly: I could also be completely wrong. Daniel |
changed name from timespec_div to timespec_idiv and test fix for fixing the rounding error
changed timespec_div to timespec_idiv
changed name from timespec_div to timespec_idiv
Author
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Your suggestion worked! Thanks! |
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I found this library quite useful and I used some functions, but I also needed an extra one that i couldn't find so here it is.
I needed to divide a timespec by an integer value in order to have a mean value from a sum of timespecs.
I hope it's helpful and Thanks!
G.Pasotti