Lab Assignment

js/index.js

@@ -4,3 +4,62 @@
 
 
 // Iteration 3: Loops
+console.log("I'm ready!");
+
+let hacker1 = "Gururaj";
+console.log(`The driver's name is ${hacker1}`);
+
+let hacker2 = "Khale";
+console.log(`The navigator's name is ${hacker2}`);
+
+if (hacker1.length > hacker2.length) {
+    console.log(`The driver has the longest name, it has ${hacker1.length} characters.`);
+  } else if (hacker2.length > hacker1.length) {
+    console.log(`It seems that the navigator has the longest name, it has ${hacker2.length} characters.`);
+  } else {
+    console.log(`Wow, you both have equally long names, ${hacker1.length} characters!`);
+  }
+
+let nameWithSpaces = "";
+for (let i = 0; i < hacker1.length; i++) {
+  nameWithSpaces += hacker1[i].toUpperCase() + " ";
+}
+console.log(nameWithSpaces.trim());
+
+let reversedName = "";
+for (let i = hacker2.length - 1; i >= 0; i--) {
+  reversedName += hacker2[i];
+}
+console.log(reversedName);
+
+if (hacker1.localeCompare(hacker2) < 0) {
+    console.log("The driver's name goes first.");
+  } else if (hacker1.localeCompare(hacker2) > 0) {
+    console.log("Yo, the navigator goes first, definitely.");
+  } else {
+    console.log("What?! You both have the same name?");
+  }
+
+
+//Palindrome  
+  function isPalindrome(str) {
+    let cleanStr = str.replace(/[^A-Za-z0-9]/g, '').toLowerCase();
+    let reversed = cleanStr.split('').reverse().join('');
+    return cleanStr === reversed;
+  }
+
+  console.log(isPalindrome("A man, a plan, a canal, Panama!")); 
+  console.log(isPalindrome("not a palindrome"));
+
+  //Bonus
+  let loremText = `
+Lorem ipsum dolor sit amet, consectetur adipiscing elit. Etiam vitae justo et sapien varius dignissim.
+Vestibulum et augue in nulla feugiat dignissim. Sed euismod, massa et facilisis posuere, ligula libero congue erat.
+Donec blandit, lorem et dignissim lacinia, justo odio facilisis odio, eget fermentum est enim in velit.
+`;
+
+let wordCount = loremText.split(/\s+/).length;
+console.log("Total number of words:", wordCount);
+
+let etCount = (loremText.match(/\bet\b/g) || []).length;
+console.log("Number of times 'et' appears:", etCount);